A solution was prepared by dissolving 43.0 g of KCl in 225 g of water. 1. Calculate the molarity of KCl in the solution if the total volume of the solution is 239 mL.

2. Calculate the molality of KCl in the solution.

0.978L

Explanation:

Using Boyle's law equation as follows;

P1V1 = P2V2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (L)

V2 = final volume (L)

According to the provided information,

P1 = 1.49 atm

V1 = 5.00 liters

P2 = 7.62 atm

V2 = ?

Using P1V1 = P2V2

1.49 × 5 = 7.62 × V2

7.45 = 7.62V2

V2 = 7.45/7.62

V2 = 0.978L