onlinebby7878
07.05.2021 •
Chemistry
A spaceship moving with an initial velocity of 58.0 meters/second experiences a uniform acceleration and attains a final velocity of 153
meters/second. What distance has the spaceship covered after 12.0 seconds?
OA.
6.96 x 102 meters
OB.
1.27 x 103 meters
OC.
5.70 x 102 meters
OD
1.26 x 102 meters
OE.
6.28 x 102 meters
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Ответ:
1.5*10^(-2)
Explanation:
0.015 is the answer for (3*10^2)*(5*10^-5)
(3*100)*(5*0.00001)
300*0.00005 = 0.015
1.5*0.001 = 0.015