![henryzx900](/avatars/47711.jpg)
henryzx900
10.02.2020 •
Chemistry
A steel cylinder contains 150.0 mol argon gas at a temperature of 25°C and a pressure of 7.04 MPa. After some argon has been used, the pressure is 2.00 MPa at a temperature of 19°C. What mass (g) of argon remains in the cylinder?
Solved
Show answers
More tips
- F Food and Cooking What is the Right Thickness for a Perfect Cream Puff?...
- F Food and Cooking What can and cannot be eaten during Lent?...
- F Food and Cooking How to Find Your Zip Code?...
- W Work and Career Can Skill Alone Make You a Professional?...
- C Computers and Internet How to Top Up Your Skype Account Without Losing Money?...
- P Philosophy Unidentified Flying Object - What is the Nature of this Phenomenon?...
- F Family and Home Protect Your Home or Apartment from Pesky Ants...
- O Other What is a Disk Emulsifier and How Does it Work?...
- F Family and Home What does a newborn need?...
Answers on questions: Chemistry
- M Mathematics Abby s graduation picnic will cost $6 if it has 3 attendees. At most how many attendees can there be if Abby budgets a total of $16 for her graduation picnic? Assume...
- E English Change the following sentence, from active to passive voice to shift the emphasis to the object of the verb takes away. Every week or so a truck takes some of the prisoners...
- H History When and where does scene one take place...
- E English What is Helen s relationship with her little sister? How does it change or evolve?...
Ответ:
The mass of argon remaining in the cylinder is 1,740 g.
The given parameters;
initial number of moles of the gas, n₁ = 150initial temperature, T₁ = 25 ⁰C = 298 Kinitial pressure of the gas, P₁ = 7.04 MPafinal pressure of the gas, P₂ = 2 MPafinal temperature of the gas, T₂ = 19 ⁰C = 292 kThe final number of moles of the gas is calculated as follows;
The molar mass of argon gas is given as;
molar mass = 40 g/mol
The mass of argon remaining in the cylinder is calculated as;
M = n x molar mass
M = 43.5 x 40
M = 1,740 g
Learn more here:link
Ответ:
There remains 1737 grams of argon gas
Explanation:
Step 1: Data given
Moles of argon gas = 150.0 moles
Temperature of the argon gas = 25.0 °C = 298 K
Initial Pressure = 7.04 MPa
Final pressure = 2.00 MPa
Final temperature = 19.0 °C
Step 2: Calculate moles of argon
p*V = n*R*T
We can say:
P/(n*T) = R/V
or P1/(n1*T1) = P2/(n2*T2)
⇒ with P1 = initial pressure = 7.04 MPa = 69.4794 atm
⇒ with n1 = initial number of moles = 150.0 moles
⇒ with T1 = The initial temperature = 25.0 °C = 298 K
⇒ with P2 = the final pressure = 2.00 MPa = 19.7385 atm
⇒ with n2 = the final number of moles = TO BE DETERMINED
⇒ with T2 = the final temperature = 19.0 °C = 292 K
7.04 / (150.0 * 298) = 2.00/(n2 * 292)
1.575 *10^-4 = 2/(292n2)
292n2 = 2/1.575 *10^-4
n2 = 43.49 moles
Step 3: Calculate mass of argon
Mass = moles * molar mass
Mass = 43.49 * 39.95 g/mol
Mass argon = 1737 grams
There remains 1737 grams of argon gas
Ответ:
c
Explanation: