A student increases the temperature of a 673 cm^3 balloon from 275 K to 460 K. Assuming constant pressure, what should the new volume of the balloon be?

Round your answer to one decimal place.

1125.75 cm³

Explanation:

We are given;

Initial volume; V1 = 673 cm³

Initial temperature; T1 = 275 K

Final temperature; T2 = 460 K

From Charles law, we can find the new volume from;

V1/T1 = V2/T2

V2 = (V1 × T2)/T1

V2 = (673 × 460)/275

V2 = 1125.75 cm³

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243

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252

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99

Es,  

251

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98

Cf,  

214

/

82

Pb

Explanation: Im not very good with this but here ya go!