A typical barometric pressure in Kansas City is 740 torr. What is this pressure in atmospheres, in millimeters of mercury, and in kilopascals?

Explanation:

Given parameters:

The barometric pressure in Kansas City  = 740torr

 Convert to mmHg, atm and kPa;

Now;

            1 atm  = 1torr

So;

          740torr = 740atm

Then;

        1 mmHg  = 1 torr

     740torr will also be 740mmHg

In kPa;

           1 atm  = 101325Pa

          740 atm  = 740 x 101325  = 74980500Pa;

  To kPa; divide by 1000

              74980.5kPa