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FIRENINJA117
22.11.2019 •
Chemistry
A0.7011-g mixture of sodium chloride and sodium nitrate is completely dissolved in water. when silver nitrate is added to the solution, 0.9805 g of solid precipitate. what is the percent by mass of chloride in the initial mixture?
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Ответ:
34.59 %
Explanation:
Sodium chloride dissolves in water as follows:
NaCl(s) → Na⁺(aq) + Cl⁻(aq)Chloride ions are then precipitated with silver ions:
Ag⁺(aq) + Cl⁻(aq) → AgCl(s)Now we use the give mass of AgCl to calculate the moles of Cl:
0.9805 g AgCl ÷ 143.32 g/mol = 6.841x10⁻³ mol AgClmol AgCl = mol Cl
6.841x10⁻³ mol Cl * 35.45 g/mol = 0.2425 g ClFinally we calculate the mass percent of Cl in the initial mixture:
0.2425g / 0.7011g *100% = 34.59 %Ответ:
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