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reinasuarez964
05.02.2020 •
Chemistry
A135-g sample of a metal requires 2.50kj to change its temperature from 19.5 degrees celsius to 100.0 degrees celsius. what is the specific heat of this metal?
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Ответ:
2500 = 0.135 x C x 80.5
2500 = 10.8765 x C
C = 230.043 J/Kg.K
hope this helps
Ответ:
The specific heat of the metal is![0.23J/g^0C](/tpl/images/0504/0965/eac25.png)
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
Q = Heat absorbed=![2.50kJ=2500J](/tpl/images/0504/0965/953d6.png)
m= mass of substance = 135 g
c = specific heat capacity = ?
Initial temperature =
= 19.5°C
Final temperature =
=100.0°C
Change in temperature ,![\Delta T=T_f-T_i=(100-19.5)^0C=80.5^0C](/tpl/images/0504/0965/b6e8f.png)
Putting in the values, we get:
The specific heat of the metal is![0.23J/g^0C](/tpl/images/0504/0965/eac25.png)
Ответ:
Hey bsf
Explanation: