A19.4 gram sample of gas is found to have a volume of 1.3 liters at 282 k and 1.2 atm. what is the molar mass of this gas? show all of the work used to solve this problem.

Molar mass of the given gas can be calculated by using the ideal gas law, which is in the formula;
PV=nRT where P is pressure, V=volume, n= no. of moles, R=ideal gas constant, and T=temperature. This equation has to be dimensionally homogeneous. Use R=0.08206 L-atm/mol-K.
PV=nRT
(1.2 atm)(1.3 L)=n(0.08206)(282K)
n=0.0674 mol
In order to find the molar mass, divide the given mass with the obtained number of moles,
19.4 g/0.0674 mol = 287.78 g/mol

Can you show a picture of the titration so i can answer ur question plz :)