Chemistry: A20g sample of iron at a temperature of 120oc is placed into a container of water. there are 300 milliliters of water in the container at a temperature of 30oc. ciron=0.444jg∘c cwater=4.184jg∘c rhowater=1gml 10. what is the final temperature of the water?

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A20g sample of iron at a temperature of 120oc

lyn94

02.01.2022

30.63 °C will be the final temperature of the water.

Explanation:

Heat lost by iron will be equal to heat gained by the water

-Q_1=Q_2

Mass of iron = m_1=20 g

Specific heat capacity of iron = c_1=0.444 J/g^oC

Initial temperature of the iron = T_1=120^oC

Final temperature = T_2 =T

$Q_1=m_1c_1\times (T-T_1)$

Volume of water = 300 ml

Density of water = 1 g/mL

Mass of water= $m_2=300 mL\times 1 g/mL = 300 g$

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=30^oC

Final temperature of water = T_2 =T

$Q_2=m_2c_2\times (T-T_3)$

-Q_1=Q_2

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

we get, T = 30.63°C

30.63 °C will be the final temperature of the water.

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