A25.00 ml sample of an aqueous solution of ba(oh)2 requires 18.45 ml of 0.01500 m hcl (aq) for its neutralization. what is the molarity of the ba(oh)2 solution?
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Ответ:
5.54 x 10⁻³ M
Further explanationGiven:
Neutralization reaction between:
25.00 ml of Ba(OH)₂18.45 ml of 0.015 M HClQuestion:
What is the molarity of the Ba(OH)₂ solution?
The Process:
Let us say the molarity of the Ba (OH)₂ solution as x M.
Step-1: prepare moles for each reagent
Step-2: neutralization
We use the ICE table to see how neutralization occurs between acid and base.
Balanced reaction:
Initial: 25x 0.277 - -
Change: - ¹/₂ · (0.277) -0.277 +¹/₂ · (0.277) +0.277
Equlibrium: - - +¹/₂ · (0.277) +0.277
Neutralization causes no excess of hydrogen or hydroxide ions in solution. In the end, the number of acid and base reactions is balanced. In other words, the two reagents have run out with nothing left.HCl acts as a limiting reagent.Step-3: calculate the molarity of the Ba(OH)₂ solution.
We consider Ba (OH) from the initial, change, and equilibrium stages.
Thus, the molarity of the Ba(OH)₂ solution is 5.54 x 10⁻³ M.
_ _ _ _ _ _ _ _ _ _
Alternative Steps
Valence of base = the number of OH⁻ ionsValence of acid = the number of H⁺ ionsNeutralization:![\boxed{ \ V_b \cdot M_b \cdot valence \ of \ base = V_a \cdot M_a \cdot valence\ of \ acid \ }](/tpl/images/0152/9008/2f841.png)
Thus the same results were obtained. The molarity of Ba (OH) ₂ solution is 5.54 x 10⁻³ M.
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