Aballoon filled with 2.00 l of helium initially at 1.15 atm of pressure rises into the atmosphere. when the surrounding pressure reaches 500. mmhg , the balloon will burst. if 1 atm = 760. mmhg , what volume will the balloon occupy in the instant before it bursts?
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Ответ:
The balloon will occupy volume of 3.53 L before getting burst
Explanation:
Initial Volume of the balloon=
Initial pressure of the atmosphere=
Final pressure of the atmosphere =
(1atm =760 mmHg)
Final Volume of the ballon =
According Boyle's Law:
The balloon will occupy volume of 3.53 L before getting burst.
Ответ:
what is the English translation, id like to help
Explanation: