Chemistry: According to ale chatelier’s principle, what happens to the equilibrium constant when the concentration of the reactants is doubled?

According to ale chatelier’s principle, what happens

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08.04.2023

The mass of water present in given amount of hydrate is 36.68 grams and number of moles of water are 2.04 moles.

Explanation:

We are given:

Mass of hydrate = 0.946 grams

Mass of water present = 0.347 grams

We need to calculate the mass of water present in 100 grams of hydrate. By using unitary method, we get:

In 0.946 g of hydrate, the amount of water present is 0.347 g

So, in 100 g of hydrate, the amount of water present will be = $\frac{0.347g}{0.946g}\times 100g=36.68g$

Hence, the mass of water present in given amount of hydrate is 36.68 grams.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of water = 36.68 g

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

$\text{Moles of water}=\frac{36.38g}{18g/mol}=2.04mol$

Hence, the number of moles of water are 2.04 moles.

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