According to the molecular orbital (mo) treatment of the no molecule, what are the bond order and the number of unpaired electrons, respectively?

Attached is the MOT of NO molecule.

1. Bond order is calculated is 

In present case, number of e- in bonding orbital = 6
number of e- in anti-bonding orbital = 1
∴ Bond-order = = 2.5

2. From the attached figure, it can be seen that NO has one unpaired electron in π* orbital.
 

8o/58*6*10power23 gives u the answer. molecules=moles*avagadrono

moles=weight/molecular wt

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