According to this decay series chart, which is the proper order of nuclear particle emission that occurs during the transition from lead-214 to llead-210?
a) lead-214 changes to bismuth-214.
b) bismuth-214 changes to polonium-214.
c) polonium-214 changes to lead-210.

Explanation:

An alpha particles is basically a helium nucleus and it contains 2 protons and 2 neutrons.  

Symbol of an alpha particle is .

A beta particle is a particle with a negatively charged electron. Symbol of a beta particle is .

According to the given question, the decay series chart along with reaction equation are as follows.

(a)  Lead-214 changes to bismuth-214.

(b)  Bismuth-214 changes to polonium-214.

(c)  Polonium-214 changes to lead-210.

Therefore, we can conclude that proper order of nuclear particle emission is beta, beta, alpha.

correct option: A. tetrahedral

Explanation:

when we talk about hydrogen bonding in water due to oxygen then need to check the number of lone pair available for hydrogen bonding because hydrogen bond form between lone pair of oxygen and hydrogen of other water molecule so there are two lone pair which forms hydrogen bond and there are also two other covalent bond with hydrogen of same molecule so total number is 4 it means they will form a tetrahedral geometry