Achemist has one solu6on that is 40% sulfuric acid and one that is 10% sulfuric acid. how much of each should she use to make 20 liters of a solu6on that is 28% sulfuric acid?
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Ответ:
12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.
Explanation:
For first solution of sulfuric acid :
C₁ = 40% , V₁ = ?
For second solution of sulfuric acid :
C₂ = 10% , V₂ = ?
For the resultant solution of sulfuric acid:
C₃ = 28% , V₃ = 20L
Also,
V₁ + V₂ = V₃ = 20L (1)
Using
C₁V₁ + C₂V₂ = C₃V₃
40×V₁ + 10×V₂ = 28×20
So,
40V₁ + 10V₂ = 560(2)
Solving 1 and 2 as:
V₂ = 20 - V₁
Applying in 2
40V₁ + 10(20 - V₁) = 560
40V₁ + 200 - 10V₁ = 560
30V₁ = 360
V₁ = 12 L
So,
V₂ = 20 - V₁ = 8L
12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.
Ответ:
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Explanation: