Acompound of formula xcl3 reacts with aqueous agno3 to yield solid agcl according to the following equation: xcl3(aq)+3agno3(aq)→x(no3)3(aq)+3agcl(s) when a solution containing 0.521 g of xcl3 was allowed to react with an excess of aqueous agno3, 1.68 g of solid agcl was formed. what is the identity of the atom x?

Aluminum

Explanation:

Mass of = 1.68 g

Molar mass of = 143.32 g/mol

Thus,

From the reaction below:

3 moles of are produced when 1 mole of undergoes reaction.

So,

1 mole of are produced when mole of undergoes reaction.

0.01172 mole of are produced when mole of undergoes reaction.

Thus, moles of = 0.0039 moles

Let the atomic mass of X = x g/mol

atomic mass of chlorine = 35.5 g/mol

Thus, Molar mass of = x + 3(35.5) g/mol = x + 106.5 g/mol

Moles = 0.0039 moles

Mass = 0.521 g

Thus, molar mass = Given mass/ Moles = 0.521 / 0.0039 = 133.5897 g/mol

So,

x + 106.5 = 133.5897

x = 27.0897 g/mol

This Atomic weight corresponds to Aluminum. Hence, X is aluminum.