cristinanina
25.02.2020 •
Chemistry
After doing multiple titrations, your NaOH solution is determined to have a mean concentration value of 0.100 M. Given you are to assume your unknown acid is 75.0% KHP, how many grams of your unknown will you need to use 15.00 mL of your 0.100 M standardized NaOH
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Ответ:
The mass of unknown acid needed is 0.230 grams
Explanation:
To calculate the number of moles for given molarity, we use the equation:
Molarity of NaOH solution = 0.100 M
Volume of solution = 15.00 mL = 0.015 L (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
The chemical reaction for the reaction of KHP and NaOH follows
By Stoichiometry of the reaction:
1 mole of NaOH reacts with 1 mole of KHP.
So, 0.0015 moles of NaOH will react with = of KHP
To calculate the number of moles, we use the equation:Moles of KHP = 0.0015 moles
Molar mass of KHP = 204.22 g/mol
Putting values in above equation, we get:
We are given:
Mass of unknown acid = 75 % of Mass of KHP
So, mass of unknown acid =
Hence, the mass of unknown acid needed is 0.230 grams
Ответ:
Steel: metallic
Propane: covalent
Calcium chloride: ionic
Water: covalent
Explanation: