Chemistry: Agalvanic cell has the overall reaction: zn(s) 2eu(no3)3(aq)  zn(no3)2(aq) 2eu(no3)2(aq) which is the half reaction occurring at the anode

Hello how is your day todayMate...

Agalvanic cell has the overall reaction: zn(s) 2eu(no3)3(aq)

avision42

10.03.2022

The half reaction occurring at anode is $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$

Explanation:

In a chemical cell, substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

$X^{n+}+ne^-\rightarrow X$

For the given chemical cell reaction:

$Zn(s)+2Eu(NO_3)_3(aq.)\rightarrow Zn(NO_3)_2(aq.)+2Eu(NO_3)_2(aq.)$

Oxidation half reaction (anode): $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$

Reduction half reaction (cathode): $Eu^{3+}(aq.)+e^-\rightarrow Eu^{2+}(aq.)$ ( × 2 )

Here, zinc is loosing electrons and is getting oxidized and europium is gaining electrons and loosing electrons.

Hence, the half reaction occurring at anode is $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$

0,0(0 оценок)