AgCL would be least soulble at 25 degrees Celcius in ___ A. pure water B. 0.1 M HNO3 C. 0.1 M CaCl2 D. 0.1 M HCL E. It is equally soluble in all of these substances.

The answer is C. 0.1MCaCl2

Explanation:

We have AgCl whose least solubility is to be determined at 25degree Celsius

so upon looking at the options given we observe C 0.1MCaCl2 and D 0.1MHCl both have chlorine ions present and we know that here common ion effect will happen that causes decreases the solubility of the AgCl here

but when Calcium chloride dissociates it gives 2 moles of chlorine ions

→

so chlorine ion will be present in more amount = as compared to the chlorine produced by HCl

→ only 1 mole of chlorine is produced.

Hence AgCl will be least soluble in 0.1M CaCl2

A lot, but depending of how much pasta/rice you´re cooking.

Explanation: There are several users of the pasta method around the Internet that define the correct amount of water with "what seems right to you", and believe it or not this migh not be a lie at all. One of the constants that I've found on this method is the instinct. Put as much water as you wish, but your boiling vessel has to look good! A recipe that generates crave at sight.