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jennymares
11.07.2019 •
Chemistry
Aliquid sample that weighs 2.585 g is a mixture of butane (c4h10) and hexane (c6h14). when the sample is combusted in an excess of oxygen, 3.929 g of water are formed.
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Ответ:
Missing question: How much butane and hexane (answer in g) were in the original sample?
Answer is: 1.138 grams of butane and 2.61 grams hexane.
Balanced chemical reactions:
1) C₄H₁₀ + 13/2O₂ → 4CO₂ + 5H₂O.
2) C₆H₁₄ + 19/2O₂ → 6CO₂ + 7H₂O.
m(H₂O) = 3.929 g.
n(H₂O) = 3.929 g ÷ 18 g/mol.
n(H₂O) = 0.218 mol.
Amount of water in both reactions is 0.218 mol, five parts from butane, seven parts from hexane.
n(H₂O) = (0.218 mol ÷ 12) · 5 = 0.091 mol; water from butane.
n(C₄H₁₀) : n(H₂O) = 1 : 4.
n(C₄H₁₀) = 0.023 mol.
m(C₄H₁₀) = 0.023 mol · 58 g/mol = 1.318 g.
Ответ:
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Explanation: