Chemistry: All common cations are smaller than all common anions except one of these a. rubidium b. calcium c. magnesium d. sodium

The solution is and Step-by-step explanation:The expression is Multiplying the term by , we get,Adding both sides by 1,Taking factor, we get,Equating the factors to 0, and Thus, the smaller value is The solution is and...

All common cations are smaller than all common anions

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cindy437596

22.03.2021

Chemistry

The solution is x=-1 and x=-0.5

Step-by-step explanation:

The expression is 2x(x+1.5)=-1

Multiplying the term x+1.5 by , we get,

$2x^{2} +3x=-1$

Adding both sides by 1,

$2x^{2} +3x+1=0$

Taking factor, we get,

$\begin{array}{r}{x^{2}+2 x+x+1=0} \\{2 x(x+1)+1(x+1)=0} \\{(2 x+1)(x+1)=0}\end{array}$

Equating the factors to 0,

$\begin{aligned}2 x+1 &=0 \\2 x &=-1 \\x &=-\frac{1}{2}\\x&=-0.5\end{aligned}$ and $\begin{aligned}x+1 &=0 \\x &=-1\end{aligned}$

Thus, the smaller value is x=-1

The solution is x=-1 and x=-0.5

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All common cations are smaller than all common anions except one of these a. rubidium b. calcium c. magnesium d. sodium

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