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Bearboy1564

24.12.2021

Chemistry

$3.14 \times 10^{23} \text{ S atoms}$

Explanation:

1. Calculate the moles of Al₂S₃

$\text{Moles of Al$_{2}$S}_{3} = \text{26.1 g} \times \dfrac{\text{1 mol}}{\text{150.16 g}} = \text{0.1738 mol Al$_{2}$S}_{3}$

2. Calculate the moles of S atoms

$\text{Moles of S atoms} = \text{0.1738 mol Al$_{2}$S}_{3} \times \dfrac{\text{3 mol S atoms }}{\text{1 mol Al$_{2}$S}_{3}} = \text{0.5214 mol S atoms}$

3. Calculate the number of S atoms

$\text{No. of S atoms} = \text{0.5214 mol S atoms} \times \dfrac{6.022 \times 10^{23} \text{ S atoms}}{\text{1 mol S atoms}} = \mathbf{3.14 \times 10^{23}} \textbf{ S atoms}$

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