alminum metal reacts with chlorine gas to give aluminium chloride if 100 gm al is added to 100 gm chlorine gas how many grams of aluminium chloride are produced?

Mass = 124 g

Explanation:

Given data:

Mass of Al = 100 g

Mass of chlorine = 100 g

Mass of aluminum chloride produced = ?

Solution:

Chemical equation:

2Al  + 3Cl₂       →    2AlCl₃

Number of moles of Cl₂:

Number of  moles = mass/molar mass

Number of moles = 100 g/ 71 g/mol

Number of moles = 1.4 mol

Number of moles of Al:

Number of  moles = mass/molar mass

Number of moles = 100 g/ 27 g/mol

Number of moles = 3.7 mol

Now we will compare the moles of AlCl₃ with Al and Cl₂.

                     Al            :             AlCl₃

                      2            :              2

                     3.7          :            3.7

                     Cl₂          :             AlCl₃

                      3            :              2

                     1.4           :            2/3×1.4 = 0.93

Less number of moles of  AlCl₃ are produced by Cl₂ thus it will act as limiting reactant.

Mass of AlCl₃:

Mass = number of moles × molar mass

Mass = 0.93 mol × 133.34 g/mol

Mass = 124 g

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