Aluminum bromide reacts with chlorine gas to produce aluminum chloride and liquid bromide,
according to the chemical equation below:
2aibr+ 3c1, 2aici, + 3br2
how many moles of aluminum chloride are made if 779 g of chlorine gas are consumed?

7.5 mol of AlCl₃ will produce.

Explanation:

Given data:

Mass of chlorine = 779 g

Moles of aluminium chloride = ?

Solution:

Chemical equation:

2AlBr₃ + 3Cl₂ → 2AlCl₃ + 3Br₂

Number of moles of Cl₂:

Number of moles = mass/ molar mass

Number of moles = 779 g / 71 g/mol

Number of moles = 11.3 mol

Now we will compare the moles of chlorine with AlCl₃ .

                        Cl₂       :       AlCl₃

                         3         :        2

                        11.3      :      2/3×11.3 = 7.5 mol

2SO2(g)+O2(g)→2 SO3(g), here reaction entropy decreases as the number of gas moles decreases from reactions to products.
HCL(g)+NH3(g)→NH4CL(s), entropy decreases as molecules of gas are converted into solid.
CO2(s)→CO2(g), entropy increases as gas is formed from a solid.
Cao(s)+CO2(g)→Caco3(s), entropy increases as gas is converted into a solid.