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halobry2003
10.01.2020 •
Chemistry
Aman heats a balloon in the oven. if the balloon initially has a volume of 0.8 liters and a temperature of 12°c, what will the volume of the balloon be after he heats it to a temperature of 300°c?
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Ответ:
1.044 L
Explanation:
Data Given
initial volume V1 of gas in balloon = 0.8 L
initial Temperature T1 of gas in balloon = 12 °C
convert Temperature to Kelvin
T1 = °C +273
T1 = 12°C + 273 = 285 K
final Temperature T2 of gas in balloon = 100°C
convert Temperature to Kelvin
T1 = °C +273
T1 = 100°C + 273 = 373 K
final volume V2 of gas in balloon = ?
Solution:
This problem will be solved by using Charles' law equation at constant pressure.
The formula used
V1 / T1 = V2 / T2
As we have to find out volume, so rearrange the above equation
V2 = ( V1 / T1 ) x T2
Put value from the data given
V2 = (0.8 L / 285 K) x 373 K
V2 = (0.0028 L/K) x 373 K
V2 = 1.044 L
So the final volume of gas in balloon= 1.044 L
Ответ:
Acceleration is a change in velocity, either an increase in speed or a change in direction. Acceleration measures the rate of change of an object's velocity. Average acceleration is calculated by dividing the change in velocity over the time.