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04.12.2019 •
Chemistry
Amixture of nitrogen and hydrogen gases, at a total pressure of 663 mm hg, contains 3.46 grams of nitrogen and 0.156 grams of hydrogen. what is the partial pressure of each gas in the mixture? pn2 = mm hg ph2 = mm hg
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Ответ:
The partial pressure of nitrogen gas is 405.76 mmHg and that of hydrogen gas is 257.24 mmHg
Explanation:
To calculate the number of moles, we use the equation:
For nitrogen gas:Given mass of nitrogen gas = 3.46 g
Molar mass of nitrogen gas = 28 g/mol
Putting values in above equation, we get:
For hydrogen gas:Given mass of hydrogen gas = 0.156 g
Molar mass of hydrogen gas = 2 g/mol
Putting values in above equation, we get:
Mole fraction of a gas is calculated by using the formula:
......(1)
For nitrogen gas:Putting values in equation 1, we get:
For hydrogen gas:Putting values in equation 1, we get:
The partial pressure of a gas is given by Raoult's law, which is:
......(2)
where,
= partial pressure of substance A
= total pressure = 663 mmHg
= mole fraction of substance A
For nitrogen gas:For hydrogen gas:Hence, the partial pressure of nitrogen gas is 405.76 mmHg and that of hydrogen gas is 257.24 mmHg
Ответ:
I am expecting that answer is 26600