Chemistry: An archer shot a 0.06 kg arrow at a target. the arrow accelerated at 5,000 m/s/s to reach a speed of 50.0 m/s as it left the bow. during this acceleration, what was the net force on the arrow to the nearest newton? * 1 point a. 3 n b. 833 n c. 300 n d. none of the above

An archer shot a 0.06 kg arrow at a target. the

smithmorgan773p35885

09.01.2022

Answer;

C. 300 N

Explanation;

From Newton second's Law of motion, the resultant force is directly proportional to the rate of change in momentum.

Therefore;

F = ma ; where F is the resultant force, m is the mass and a is the acceleration.

Therefore;

F = 0.06 kg × 5,000 m/s/s

= 300 N

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jaymoney0531

31.05.2021

Explanation:

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