queenkimm26
25.01.2020 •
Chemistry
An atom of a particular element is traveling at 1.00% of the speed of light. the de broglie wavelength is found to be 3.31 × 10-3 pm. which element is this? prove it.
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Ответ:
The movement of sounds, in the same manner, is called wavelength.
The correct element is Ca.
The data in the question is as follows:-
Speed of atom is 1% of the speed of light De-Broglie wavelength =The formula we will used is
The data is given is as follows:-
m = mass of the particle h = planks constant v = speed of particle λ = wavelengthNow we will put the values in the formula and solve the equation.
After solving the value of m is
Now in the given problem, the solution is as follows:-
After solving the equation the answer is 40.3
Hence, the 40.3 is the mass of calcium.
For more information, refer to the link:-
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Ответ:
The given atom is of Ca.
Explanation:
Given data:
Speed of atom = 1% of speed of light
De-broglie wavelength = 3.31×10⁻³ pm (3.31×10⁻³ / 10¹² = 3.31×10⁻¹⁵ m)
What is element = ?
Solution:
Formula:
m = h/λv
m = mass of particle
h = planks constant
v = speed of particle
λ = wavelength
Now we will put the values in formula.
m = h/λv
m = 6.63×10⁻³⁴kg. m².s⁻¹/3.31×10⁻¹⁵ m ×( 1/100)×3×10⁸ m/s
m = 6.63×10⁻³⁴kg. m².s⁻¹/ 0.099×10⁻⁷m²/s
m = 66.97×10⁻²⁷ Kg/atom
or
6.69×10⁻²⁶ Kg/atom
Now here we will use the Avogadro number.
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
Now in given problem,
6.69×10⁻²⁶ Kg/atom × 6.022 × 10²³ atoms/ mol × 1000 g/ 1kg
40.3×10⁻³×10³g/mol
40.3 g/mol
So the given atom is of Ca.
Ответ: