An electrochemical cell is powered by the half reactions shown below.
ag+(aq) + e– ag(s) eo = +0.80 v
pb2+(aq) + 2e– pb(s) eo = –0.13 v
which value represents the overall electric cell potential?
use ecell = ered, cathode – ered, anode.
–0.13 v
–0.93 v
+0.67 v
+0.93 v
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Ответ:
To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign.
Pb(s) --> Pb2+ +2e- E0 = +0.13 V
Ag+ + e- ---> Ag E0 = +0.80 V
Adding up the E0's would yield an overall electric cell potential of +0.93 V.
Ответ:
J. J. Thomson
Just took the test
Explanation: