Chemistry: An ideal gas with γ = 1.67 has an initial temperature of 0°C, initial volume of 10.0 liters, and initial pressure of 1.00 atm. Then the gas is expanded adiabatically to a volume of 10.4 liters. What is the new temperature? (1 point)

An ideal gas with γ = 1.67 has an initial temperature

tori6886

31.01.2022

T = 9.74°C

Explanation: An ideal gas in a quasi-static adiabatic process follows the equation: $pV^{\gamma} = constant$ .

So:

$1.10^{1.67} = constant$

constant = 46.7735

Adiabatic conditions can be written as:

$TV^{\gamma-1}=constant$

Then, new temperature is

$T.(10.4)^{1.67-1}=46.7735$

$T.(10.4)^{0.67}=46.7735$

$T = \frac{46.7735}{4.802}$

T = 9.74°C

The new temperature is 9.74°C.

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dulcejuarez2005

06.08.2021

No, because he did not test anything, he asked people´s opinion, Hope this helps! PLEASE GIVE ME BRAINLIEST =)

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