aaanderson59
28.12.2019 •
Chemistry
An unknown triprotic acid (h3a) is titrated with naoh. after the titration ka1 is determined to be 0.0053 and ka2 is determined to be 1.5e-07. the ph at the second equivalence point of the titration is measured as 8.469. what is ka3 for this triprotic acid?
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Ответ:
Ka3 for the triprotic acid is 7.69*10^-11
Explanation:
Step 1: Data given
Ka1 = 0.0053
Ka2 = 1.5 * 10^-7
pH at the second equivalence point = 8.469
Step 2: Calculate Ka3
pKa = -log (Ka2) = 6.824
The pH at the second equivalence point (8.469) will be the average of pKa2 and pKa3. So,
8.469 = (6.824 + pKa3) / 2
pKa3 = 10.114
Ka3 = 10^-10.114 = 7.69*10^-11
Ka3 for the triprotic acid is 7.69*10^-11
Ответ: