Analysis of a compound containing only C and Cl revealed that it contains 33.33 % C atoms by number and has a molar mass of 248.75 g/mol. What is the molecular formula of this compound?
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Ответ:
Molecule formula is C8Cl4
Explanation:
Empirical formula of a compound is it's simplest formula while the molecular formula gives the exact number of moles of atoms of the component elements in one mole of the compound.
To calculate the molecular formula;
Step 1:
Write the elements in the compound with their percentage quantities.
Carbon = 33.33%
Chlorine = 100 - 33.33 = 66.67%
Step 2:
Divide both components by its relative atomic mass
C = 12, Cl = 35.5
Carbon 33.33/ 12 = 2.7775
Chlorine 66.67/ 35.5 =1.8780
Step 3: divide both values by the smallest
1.8780 is the smallest
So therefore,
2.7775/ 1.8780 = 1.4790 = ~2
1.8780/ 1.8780 = 1
Empirical formulae = C2Cl
(C2Cl)x = 248.75
(12*2 + 35.5)x = 248.75
(59.5)x = 248.75
x = 248.75 / 59.5
x = 4.18 = 4
Molecular formula = C8Cl4
Ответ:
Given data:
Volume of solution: 500 ml
Mass of 10 ml solution: 10.7 g
Density of whole solution: ?
Solution:Mass of 500 ml solution : 10.7/10 * 500 = 535 g
Density = Mass/ volume
Putting values in formula :
D = 535/500 = 1.07 g/ml
Hence Density = 1.07 g/ml