Anurse practitioner orders medrol to be given 1.5 mg/kg of body weight. if a child weighs 72.6lb and the available stock of medrol is 20.mg/ml, how many ml do you give to the child

Answer is: 2,469 mL give to the child.
The mass m in kilograms (kg) is equal to the mass m in pounds (lb) times 0,45359237: m(child) = 72,6 · 0,045359237 = 32,93 kg.
m(Medrol) = 32,93 kg · 1,5 mg/kg.
m(Medrol) = 49,39 mg.
d(Medrol) = 20,0 mg/mL.
V(Medrol) = m(Medrol) ÷ d(Medrol).
V(Medrol) = 49,39 mg ÷ 20 mg/mL.
V(Medrol) = 2,469 mL.

Particles of the substance are in liquid state will gain kinetic energy between positions C and D.

Explanation:

Problem it tells us that between B an C the substance is solid, but I would say that is solid between A and B while between B and C it is a melting process in which particles will gain energy to transform from solid to liquid.

Now between C and D the particles of the liquid will receive energy which is transformed in kinetic energy so the participles will move faster.

Between D and E the particles the energy received is spent by the particles to pass from liquid state to vapors state.