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fcccxx54311

15.08.2022

Chemistry

The pK_a of the X-281 medicne is 4.29.

Explanation:

Concentration of medicine in solution = [HA]=c=0.079 M

$HA\rightleftharpoons A^+H^+$

Initially

c 0 0

At equilibrium

(c-x) x x

The expression of an dissociation constant K_A is given by :

$K_a=\frac{[A^-][H^+]}{[HA]}$

$K_a=\frac{x\times x}{(c-x)}$ ..[1]

The pH of the solution = 2.70

$pH=-\log[H^+]$

$2.70=-\log[H^+]=-\log[x]$

$x=10^{-2.70}=0.001995 M$ ..[2]

Using [2] in [1]

$K_a=\frac{0.001995 M\times 0.001995 M}{(0.079-0.001995 M)}$

$K_a=5.170\times 10^{-5}$

The pK_a of the medicine :

$pK_a=-\log[K_a]=-\log[5.170\times 10^{-5}]=4.29$

The pK_a of the X-281 medicne is 4.29.

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