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ddaaaeeee2960
08.04.2020 •
Chemistry
Apply Concepts
Draw a closed series circuit with two
What would happen if one of the light bulbs bio
les circuit with two light bulbs, a battery, and a switch,
he light bulbs blows out?
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Ответ:
The empirical formula for the given compound is![Al_2S_3](/tpl/images/0047/5633/5dfff.png)
Explanation:
Let us assume that the mass of the compound be 100 grams.
So, the percentage of the elements will be equal to their respective masses.
Mass of aluminium = 35.94 g
Mass of sulfur = 64.06 g
To find the empirical formula for a compound, we follow some steps:
Step 1: Converting the given masses of the elements into moles.To calculate moles, we use the equation:
Moles of aluminium =![\frac{35.94g}{27g/mol}=1.33mol](/tpl/images/0047/5633/d4ca5.png)
Moles of sulfur =![\frac{64.06g}{32g/mol}=2mol](/tpl/images/0047/5633/01b2b.png)
Step 2: Now, dividing each calculated moles by the smallest number of moles, which is 1.33 moles, to calculate the mole ratio of elements.Mole ratio of aluminium =![\frac{1.33}{1.33}=1](/tpl/images/0047/5633/54713.png)
Mole ratio of sulfur =![\frac{2}{1.33}=1.5](/tpl/images/0047/5633/ed3a8.png)
Step 3: Converting the mole ratio into whole number ratio.Multiplying both the ratios by 2, to make both the mole ratios to be a whole number.
Mole ratio of aluminium =![1\times 2=2](/tpl/images/0047/5633/6b04e.png)
Mole ratio of sulfur =![1.5\times 2=3](/tpl/images/0047/5633/00d58.png)
Step 4: Writing each mole ratio as the subscripts of the elements to make the empirical formula.Empirical formula for the given compound is![Al_2S_3](/tpl/images/0047/5633/5dfff.png)