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Emptypockets451
03.07.2019 •
Chemistry
Areaction of 55.1 g of na and 31.1 g of br2 yields 35.4 g of nabr. what is the percent yield?
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Ответ:
So,
% yield equals actual mass of product divided by theoretical mass of product times 100%.
1. First, write the balanced reaction.
2. Since we are given the masses of both reactants, we need to do a Limiting Reactant calculation. Calculate the theoretical masses of product produced by each reactant, assuming excess of the other reactant.
a.![\frac{55.1g\ Na}{22.99g/mol}\ *\frac{1mol\ NaBr}{1mol\ Na}\ =2.40mol\ NaBr](/tpl/images/0047/6675/3d7f9.png)
b.![\frac{31.1g\ Br_2}{159.8g/mol}\ *\frac{1mol\ NaBr}{0.5mol\ Br_2}\ =0.389mol\ NaBr](/tpl/images/0047/6675/5c019.png)
c. Bromine is the limiting reactant, and the theoretical mass of NaBr is:
3. Now, we can calculate % yield.
So, the percent yield is 88.5%.
Hope this helps!
Ответ:
A hypothetical wave has a frequency of 1.0 x 10 Hz. What is its hypothetical, approximate wavelength? ... What is its hypothetical, approximate ... State in which region of light this wave exists. E = hv. 564 × 10. − 25. J =.
Explanation:
The equation that relates wavelength, frequency, and speed of light is ... What is the wavelength of a electromagnetic wave that has a frequency of 4.95×1014 ... of an electromagnetic wave having 3.28×10−19 J of energy?