Arectangular fence is 3 times as long as it is wide. the perimeter is 60ft. find the dimensions of the fence

The length of the fence is 22.5ft and the width of the fence is 7.5ft.

Explanation:

To solve this problem we will turn this question into an equation.

The equation for the perimeter of a rectangle is 2l + 2w = perimeter.

In the question we were given the perimeter so we can go ahead and plug this in.

2l + 2w = 60

In the question we are also told that the fence is 3 times as long as it is wide. This means that 1l = 3w. We can now subsitute l for 3w so that we only have one variable.

2(3w) + 2w = 60

Now we can simply use algebra to solve for w.

6w + 2w = 60

8w = 60

w = 7.5

Now that we know the value of w we can find the value of l since we know 1l = 3w.

l = 3w

l = 3(7.5)

l = 22.5

The length of the fence is 22.5ft and the width of the fence is 7.5ft.

Ten to the negative second power L over one cL is the one among the following choices that is a possible equivalence that can be used in a conversion. The correct option among all the options that are given in the question is the third option or option "C". I hope the answer helps you.