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lorenzomendi1011
02.03.2020 •
Chemistry
As part of Lab 4 you will make and standardize a solution of NaOH(aq). Suppose in the lab you measure the solid NaOH and dissolve it into 100.0 mL of water. You then measure 0.2000 g of KHP (204.22 g/mol) and place it in a clean, dry 100-mL beaker, and then dissolve the KHP in about 25 mL of water and add a couple of drops of phenolphthalein indicator. You titrate this with your NaOH(aq) solution and find that the titration requires 9.78 mL of NaOH(aq). Part 1: How many moles of KHP are in your sample
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Ответ:
The moles of KHP in the sample is![9.79\times 10^{-4}mol](/tpl/images/0530/1949/9a0d1.png)
Explanation:
To calculate the number of moles, we use the equation:
Given mass of KHP = 0.2000 g
Molar mass of KHP = 204.22 g/mol
Putting values in above equation, we get:
Hence, the moles of KHP in the sample is![9.79\times 10^{-4}mol](/tpl/images/0530/1949/9a0d1.png)
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