Asolution is made by dissolving 2.5 moles of sodium chloride (nacl) in 198 grams of water. if the molal boiling point constant for water (kb) is 0.51 °c/m, what would be the boiling point of this solution? show all of the work needed to solve this problem.
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Ответ:
198 g / 1000 => 0.198 Kg
molality = moles solute / volume
molality = 2.5 / 0.198
molality = 12.626 mol/kg
NaCl dissociates to form 2 ions
increase in boiling point = molality * i * Kb
12.626 * 2 * 0.51 => 12.87 ºC
Water boils at 100.00 degrees Celsius , therefore:
12.87 + 100.00 => 112.87ºC
Ответ:
Such a solution is called a solution because it contains the maximum amount of solute that can be dissolved in the solvent at a given temperature. If a solution contains less solute than this maximum amount, it is an unsaturated solution.
Explanation: