Astudent sets up two reactions. reaction 1 uses 0.170 mol/l of reactant, and reaction 2 uses 0.400 mol/l of reactant. how many times faster is reaction 2 compared to reaction 1?
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Ответ:
n = 0.400 molL / 0.170 mol/L
n = 2.35 times
Thus, the second rate is 2.35 times the 1st rate.
Ответ:
[Rate]2 = 2.35[Rate]1
Explanation:
Rate of reaction is given by:
Rate1= k[reactants]1= k[0.170moles]
Rate2= K]reactants]2= k[0.400moles]
Rate2 ÷ Rate1
[Rate]2/[Rate]1= 2.35
[Rate]2= 2.35[rate]1
Ответ: