SushiMagic
08.10.2019 •
Chemistry
At 1 atm, how much energy is required to heat 39.0 g of h2o(s at –24.0 °c to h2o(g at 121.0 °c?
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Ответ:
Δt = 121 - -24 = 145
q = 39 × 4.18 × 145
q = 23637.9 J
Ответ:
Explanation:
F2 is oxidising agentSi is reducing agentSi is oxidisedF2 is reducedSi= 0, F=0Si =+4, F=-1