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lexybellx3
31.01.2020 •
Chemistry
At a certain temperature, a mixture of 2 gases, 11.2 g of oxygen and 104.75 of krypton exert a total pressure of 4.25 atm. what is the partial pressure of each gas in mm hg?
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Ответ:
Pressure of O₂ = 0.93 atm
Pressure of krypton = 3.32 atm
Explanation:
This problem can be solved by using Dalton's Law of Partial Pressures, which states that the partial pressure of a component of a gaseous mixture depends on the mole ratio of said component and the total pressure of the gaseous mixture.
Pₐ = Xₐ * Ptotal
P ₐ - the partial pressure of component a
χ ₐ - its mole fraction in the mixture
P total - the total pressure of the mixture
The moles of the two gases are:
moles of O₂ = 11.2/32 = 0.35 moles
moles of krypton = 104.75/83.8 = 1.25 moles
Total moles = 1.25 + 0.35 = 1.6 moles
Xₐ = number of moles of a /total moles in mixture
Pressure of O₂ = 0.35/1.6 *4.25 = 0.93 moles
Pressure of krypton = 1.25/1.6 *4.25 = 3.32 moles
Ответ:
6733.5 g of NaCl
Explanation:
We can assume that the salt solution is a saline solution which contains NaCl in water at 0.90%, whose density is 1.005 g/ml.
So we need to apply the density concept to solve the question.
Density = mass / volume
We convert dL to mL → 67 dL . 100mL / 1 dL = 6700 mL
Density = mass / volume
Volume . Density = mass
6700 mL . 1.005 g = 6733.5 g of NaCl