At a certain temperature, the K p Kp for the decomposition of H 2 S H2S is 0.834 . 0.834. H 2 S ( g ) − ⇀ ↽ − H 2 ( g ) + S ( g ) H2S(g)↽−−⇀H2(g)+S(g) Initially, only H 2 S H2S is present at a pressure of 0.150 atm 0.150 atm in a closed container. What is the total pressure in the container at equilibrium?
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Ответ:
Total pressure = 0.2798 atm
Explanation:
Step 1: Data given
Kp = 0.834
Initially, only H2S is present at a pressure of 0.150 atm
Step 2: The balanced equation
H2S(g)⇄ H2(g) + S(g)
Step 3: The initial pressure
pH2S = 0.150 atm
pH2 = 0 atm
pS = 0 atm
Step 3: The pressure at the equilibrium
For 1 mol H2S we'll have 1 mo lH2 and 1 mol S
pH2S = 0.150 - X atm
pH2 = X atm
pS = X atm
Step 4: Calculate Kp
Kp = (pS*pH2)/(pH2S)
0.834 = X² / (0.150 - X)
X = 0.1298
pH2S = 0.150 - 0.1298 = 0.0202 atm
pH2 = 0.1298 atm
pS =0.1298 atm
Kp = (0.1298*0.1298) / 0.0202
Kp = 0.834
The total pressure = pH2S + pH2 + pS
Total pressure = 0.0202 atm+ 0.1298 atm+ 0.1298 atm
Total pressure = 0.2798 atm
Ответ:
The chlorine isotope with 18 neutrons has an abundance of 0.7577 and a mass number of 35 amu. To calculate the average atomic mass, multiply the fraction by the mass number for each isotope, then add them together.