jasonoliva13
11.05.2021 •
Chemistry
Balloon has a volume of 600-ml at temperature of 360 K. If the temperature of the balloon drops to 250 K, find the volume
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Ответ:
V₂ ≈416.7 mL
Explanation:
This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.
V₁ / T₁ = V₂ / T₂where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.
The balloon has a volume of 600 milliliters and a temperature of 360 K, but the temperature then drops to 250 K. So,
V₁= 600 mL T₁= 360 K T₂= 250 KSubstitute the values into the formula.
600 mL /360 K = V₂ / 250 KSince we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.
250 K * 600 mL /360 K = V₂ / 250 K * 250 K 250 K * 600 mL/360 K = V₂The units of Kelvin cancel, so we are left with the units of mL.
250 * 600 mL/360=V₂416.666666667 mL= V₂Let's round to the nearest tenth. The 6 in the hundredth place tells us to round to 6 to a 7.
416.7 mL ≈V₂The volume of the balloon at 250 K is approximately 416.7 milliliters.
Ответ:
A
Explanation: