Be sure to answer all parts. what is the poh of 2.80 m ba(oh)2 solution? is the solution neutral, acidic, or basic? the poh of the solution is:

POH can be calculated by the negative logarithm of [OH⁻] .
pOH = -log [OH⁻]
pH scale is used to determine how acidic/ neutral or basic a solution is. By knowing the pOH the pH can be calculated, as;
pH + pOH = 14
pH = 14 - pOH
dissociation of Ba(OH)₂ is as follows;
Ba(OH₂) ---> Ba²⁺ + 2OH⁻ 
1 mol Ba(OH₂) dissociates into 2 OH⁻ moles
Therefore molarity of OH⁻ is twice as much as the molarity of  Ba(OH₂).
[OH⁻] = 2 x 2.80 M
        = 5.6 M
pOH = -log 5.6
         = -0.75
pH = 14 - - 0.75
     = 14.75
when the pOH is a negative value this means that the pH is greater than 14. 
Usually pH scale is from 1-14, with 1 being very acidic and 14 being very basic. Since pH is greater than 14 this means that the solution is strongly basic. 

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Explanation: