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Morghan7153
31.08.2019 •
Chemistry
By titration it is found that 68.5 ml of 0.154 m naoh(aq) is needed to neutralize 25.0 ml of hcl(aq). calculate the concentration of the hcl solution.
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Ответ:
The concentration of 25 mL of HCl solution needed to neutralize 68.5 mL of 0.154 M NaOH is 0.422 M
We'll begin by calculating the number of mole of NaOH in the solution. This can be obtained as follow:
Volume of NaOH = 68.5 mL = 68.5 / 1000 = 0.0685 L
Molarity of NaOH = 0.154 M
Mole of NaOH =?Mole = Molarity × Volume
Mole of NaOH = 0.154 × 0.0685
Mole of NaOH = 0.010549 moleNext, we shall determine the number of mole of HCl needed to react with 0.010549 mole of NaOH. This can be obtained as follow:
NaOH + HCl ⇒ NaCl + H₂O
From the balanced equation above,
1 mole of NaOH reacted with 1 mole of HCl.
Therefore,
0.010549 mole of NaOH will also react with 0.010549 mole of HCl.
Finally, we shall determine concentration of the HCl solution. This can be obtained as follow:
Volume of HCl = 25 mL = 25 / 1000 = 0.025 L
Mole of HCl = 0.010549 mole of HCl.
Molarity of HCl =?Molarity = mole / Volume
Molarity of HCl = 0.010549 / 0.025
Molarity of HCl = 0.422 MTherefore, the concentration of the HCl solution needed for the reaction is 0.422 M
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Ответ:
The concentration of the HCl solution : 0.421 m
Further explanationTitration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range
Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.
An acid-base titration there will be a change in the pH of the solution.
From this pH change a Titration Curve can be made which is a function of acid / base volume and pH of the solution
Acid-base titration formula
Ma. Va. na = Mb. Vb. nbMa, Mb = acid base concentration
Va, Vb = acid base volume
na, nb = acid base valence
Neutralization Reaction :
NaOH + HCl ⇒ NaCl + H₂O
68.5 ml of 0.154 m NaOH
25.0 ml of HCl
Acid-base titration formula
Ma. Va. na = Mb. Vb. nb
a = NaOH, b = HCl(both have valence 1)
0.154 m . 68.5.1 = Mb . 25 . 1
![\rm Mb=\dfrac{0.154\times 68.5}{25}\\\\Mb=\boxed{\bold{0.421\:m}}](/tpl/images/0214/1048/0bfdc.png)
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A) A very thin atmosphere and temperatures wary from 427 degrees to -189 degrees Celsius (800 to -292 degrees Fahrenheit).
Explanation: