C5H12 8 O2 → 5 CO2 + 6H20
How many grams of carbon dioxide will form from the combustion 320.0 grams of
C5H12 with excess oxygen?

976.8 g

Explanation:

C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂0 (1)

number of moles of reaction 1 can be shown as;

1 : 8 → 5 : 6

thus, 5 moles of CO₂ will form from the combustion of 1 mole of C₅H₁₂

molecular weight of CO₂ = 44 g/mol

molecular weight of C₅H₁₂ = 72 g/mol

mass of C₅H₁₂ = 320 g

number of moles of C₅H₁₂ = mass ÷ molecular weight = 320 / 72 = 4.44 moles

thus, number of moles of CO₂ formed = 5 * 4.44 = 22.2 moles

mass of CO₂ formed = 22.2* 44 = 976.8 g