Calculate ∆h0 for the following reaction. br2(
g. → br2(l)∆hf0 br2(
g. =30.91 kj/mol; ∆hf0 br2 (l) =0 kj/mol)

From the balance chemical reaction, it can be seen that a gaseous bromine is converted to liquid bromine. The heat of reaction is equal to the heat of the product minus the heat of the reactant. Following this, the Δhf0 is equal to,
                                       Δhf0 = (0 kJ/mol) - (30.91 kJ/mol)
                                            Δhf0 = -30.91 kJ/mol

Name of the ether is dimethyl ether.

Explanation:

When alkyl groups are attached to an oxygen atom then the resulting compound is known as an ether.

While writing the name of ethers the alkoxy side which is the shorter side is named first and then the other side is named.

For example, contains two methyl groups so a prefix "di" will be added to it name.

Hence, its name is dimethyl ether.

Thus, we can conclude that name of the ether is dimethyl ether.