Calculate molarity of an aqueous solution of Sucrose containing
3.42g in 1 litre of water.​

50.9 g of Ag

Explanation:

Reaction is:

Cu (s) + 2AgNO₃(aq)  →  2Ag (s) + Cu(NO₃)₂ (aq)

1 mol of Cu react to 2 moles of silver nitrate in order to produce 2 moles of solid silver and 1 mol of copper (II) nitrate.

We assume, the silver nitrate in excess.

We determine moles of copper → 15 g . 1mol / 63.55 g = 0.236 moles

Ratio is 1:2. 1 mol of copper produce 2 moles of silver

0.236 moles of Cu will produce (0.236 . 2) / 1 = 0.472 moles of Ag

We deterine mass of silver:

0.472 mol . 107.87 g /mol = 50.9 g