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Baby010391
20.03.2021 •
Chemistry
Calculate the change in heat (Q) that occurs when 27.58grams of liquid water at 16°C heats to water vapor at 62°C. (cp = 4.184 J/g°C)
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Ответ:
5308.16J
Explanation:
Using the formula;
Q = m × cp × ∆T
Where;
Q = change in heat (J)
m = mass of substance (g)
cp = specific heat capacity (4.184 J/g°C)
∆T = change in temperature (°C)
According to the information given in this question;
Q = ?
m = 27.58 grams
cp = 4.184 J/g°C
∆T = 62°C - 16°C = 46°C
Using Q = m × cp × ∆T
Q = 27.58 × 4.184 × 46
Q = 5308.157
Q = 5308.16J
Ответ:
D
Explanation: